anagram in c

hello,
i have created a program in c trying to check if two strings (size 30) give by the user are anagrams of each other but up till now i have the following code and can't find my way out ...
PS: in order not to have to give the words each time i have assign them in vars w1 & w2

the code is the following:

#include <stdio.h>
#include <string.h>

int main() {
    char w1[30] = "daager", w2[30] = "garden", *p1=w1 ,*p2=w2;
    int countW1[30], counterW2[30];
    int j=0, i=0,k=0, count=0;
    
    //elegxos an oi dio lexeis exoun to idio mikos.
    if (strlen(w1) == strlen(w2)){
       printf("same size w1= %ld w2 = %ld!\nchecking chars...\n", strlen(w1),strlen(w2));
        
       }
 
    //counting occurance of letters in first && second word
    for (i=0;i<strlen(w1);i++) {
        count = 0;
        for (k =0;k<strlen(w1);k++)
        {
            if (w1[i] == w1[k]) {
                countW1[i]++;
            }
            if (w2[i] == w2[k]) {
                counterW2[i]++;
            }
            if (w1[i] == w2[k] && countW1[i] == counterW2[k]) {
                printf("Brethike %c fores %d\n",w1[i], countW1[i]);
            }
        }
        printf("Char %c occurance is: %d times in first word\n",w1[i],countW1[i]);
        printf("Char %c occurance is: %d times in Second word\n",w2[i],counterW2[i]);
    }

    printf("\n\n");
        
    //checking chars and occurances
    for (p1=w1; *p1!='\0'; *p1++) {
        for (p2=w2; *p2!='\0'; *p2++) {
           if (*p1 == *p2) {
               
                
            }
        }
    }
return 0;
}

thanks