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java.net.ProtocolException: Can't reset method: already connected

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hi guys, im getting this error but i don´t know why.

java.net.ProtocolException: Can't reset method: already connected

Code:
public void seek(String web)
        {
             URL url;
                    try{
                     String urlParameters =
                     "fName=" + URLEncoder.encode("???", "iso-8859-1") +
                     "&lName=" + URLEncoder.encode("???", "iso-8859-1");
                    url = new URL(web);
                    connection = (HttpURLConnection)url.openConnection();
                    System.out.println(connection.getHeaderFields());
                    connection.setRequestMethod("GET");
                    connection.setRequestProperty("Content-Type", "application/x-www-form-urlencodeda");
                    //connection.setRequestProperty("Content-Length", "0");
                    connection.setRequestProperty("Content-Language", "en-US");
                    
                    connection.setUseCaches(true);
                    connection.setDoInput(true);
                    connection.setDoOutput(true);

                    //Envio
                    DataOutputStream wr = new DataOutputStream(connection.getOutputStream());
                    wr.writeBytes (urlParameters);
                    wr.flush();
                    wr.close();

                    //Resposta
                    InputStream is = connection.getInputStream();
                    BufferedReader rd = new BufferedReader (new InputStreamReader(is));
                    String line;

                    response = new StringBuffer();

                    while((line = rd.readLine()) != null)
                     {
                         response.append(line);
                         response.append('\r');
                     }

                    rd.close();
                    lastwww = web;
                    say();
                    read(response);
                    clean(response);
                    
       
            }catch(Exception e)
            {
                e.printStackTrace();
            }
        }


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